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orAClE 用SQL查询一个时间段每天的数据量

按日做汇总啊:select trunc(datecol) 日期,sum(数量) 数量和,count(1) 数据量 from tablex where to_char(datecol,'yyyymm') = '201305' group by trunc(datecol);

select * from 表 where to_char(TempDate,'hh24:mi') between '00:00' and '11:00' 我在PLSQL里面必须这样写,只写小时会仅限制到最后那天的11点。

使用Oracle 函数extract(fmt from d)获取日期中的特定部分: select count(*) from table where SQL> select * from table where createdate between to_date('2010-9-1','yyyy-MM-dd') and to_date('2010-10-1','yyyy-MM-dd') and EXTRACT(hour...

可以写一个简单的procedure来实现,原理是遍历日期范围,并查询日期资料笔数,写入表。 数据源表test03 1 2016-06-01 1 2 2016-06-02 1 3 2016-06-05 1 4 2016-06-04 1 5 2016-06-04 1 procedure代码如下: create or replace procedure loop_by_dat...

还有这么到的???2015-09-01到2014-09-12 select date,count(*) as number from table_name where date = '2015-09-01' union select date,count(*) as number from table_name where date = '2015-09-02' 如果天数比较少 可以这么干,如果比...

select t.idate, t.t_num1, t1.t_num2 from (select to_char(idate, 'yyyy/mm/dd hh') || '点' as idate, sum(t_num1) as t_num1 from a group by to_char(idate, 'yyyy/mm/dd hh') || '点') t left join (select to_char(idate, 'yyyy/mm/dd hh...

哪里要这么复杂....鉴于你按每10分钟来连续排列有点奇怪..我写了一个按照日期来连续的sql.. select b.name, min(b.visit_time), max(b.visit_time)from ( select a.*, (a.visit_time - rownum) cc from ( select * from vister order by name, v...

是这个意思吗? 如果是用如下语句,不是的话请另外说明 with t as (select rownum rn from dual connect by rownum

select xx.time as "时间",count(id) as "条数" from record xx where xx.time between '2014-09-01' and '2014-10-01' group by xx.time;

用to_char函数即可。 如emp表中数据如下: 要查询hiredate的日期为1981年1月1日到1981年5月1日之间的数据,可用如下语句: select * from emp where to_char(hiredate,'yyyy-mm-dd') between '1981-01-01' and '1981-05-01';查询结果:

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